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problem on finding of a linear transformation : Linear Algebra : B.Sc.Mathematics

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    * V/W forms a vector space.   * Find the coordinates of 𝜶 = (4 ,5 ,6) w.r.t.  x=(1,1,1),y = (-1,1,1),z = (1,0,-1)  *dim ( W1 + W2 ) = dim ( W1 ) + dim ( W2) - dim ( W1 ⋂ W2 )   *  If 𝜶 = ( 1 , -1 , 0 ) , 𝜷 = ( 2 , 1 , 3 ) find a basis for R3 containing 𝜶 and 𝜷  *  Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2  } forms a basis of V3 ( F )  * Theorem on Linear Dependence  * linear sum of subspaces * What is a vector space * linear span of a set      * L ( S ) = L ( S' )  * Theorem on vector space      * Historical Introduction to Linear Algebra   * Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W              to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒  𝜶 - 𝞫 𝞊 W                               ...

[ grad a , grad b , grad c ] =0 : Integral Calculus : B.Sc.Mathematics

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   *   Historical Background of Integral Calculus  * Few problems on derivative of a vector function    * Derivative of a vector function #vector #calculus #vector calculus      #gradient #vector #integral-calculus #[grad-a-grad-b-grad-c]=0 #iit #jee #iit-jee #jeemains #iitjeepreperation 

RANK-NULLITY THEOREM : LINEAR ALGEBRA : B.SC.MATHEMATICS

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  For a video explanation, click here 👉 https://youtu.be/iazotp3QIsg   * dim( V/W) = dimV-dimW * V/W forms a vector space.   * Find the coordinates of 𝜶 = (4 ,5 ,6) w.r.t.  x=(1,1,1),y = (-1,1,1),z = (1,0,-1)  *dim ( W1 + W2 ) = dim ( W1 ) + dim ( W2) - dim ( W1 ⋂ W2 )   *  If 𝜶 = ( 1 , -1 , 0 ) , 𝜷 = ( 2 , 1 , 3 ) find a basis for R3 containing 𝜶 and 𝜷  *  Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2  } forms a basis of V3 ( F )  * Theorem on Linear Dependence  * linear sum of subspaces * What is a vector space * linear span of a set      * L ( S ) = L ( S' )  * Theorem on vector space      * Historical Introduction to Linear Algebra   * Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W              to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒  𝜶 - 𝞫 𝞊 W     ...

dim( V/W) = dimV-dimW : Linear Algebra : B.Sc.Mathematics

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For a video explanation, click here 👉 https://youtu.be/8wmtNrUwsjI  Statement :        Suppose W is a subspace of a finite dimensional vector space V(F) then dim( V/W) = dimV-dimW Proof :       * V/W forms a vector space

Linearly independent & dependent vectors : Linear Algebra : B.Sc.Mathematics

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For a video explanation, click here 👉 https://youtu.be/b0KvzStFHAc   Linearly Independent Vectors :          Let 𝜶 1 , 𝜶 2 , … , 𝜶 n be any n vectors in a vector space V ( F ). Then the      vectors 𝜶 1 , 𝜶 2 ,  … , 𝜶 n are   called Linearly Independent vectors , if there exists       Scalars a 1 , a 2 , … , a n   such that  a 1 𝜶 1 + a 2 𝜶 2 + … + a n 𝜶 n = 0 implies a 1 = a 2 = … = a n = 0.      Linearly Dependent Vectors :          Let 𝜶 1 , 𝜶 2 , … , 𝜶 n be any n vectors in a vector space V ( F ). Then the      vectors 𝜶 1 , 𝜶 2 , … , 𝜶 n are   called Linearly Dependent vectors , if there exists scalars      a 1 , a 2 , … , a n  not all zero  such that   a 1 𝜶 1 + a 2 𝜶 2 + … + a n 𝜶 n = 0   

A singleton set with non-zero vector is Linearly Independent : LInear Algebra : B.Sc.Mathematics

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       Theorem :      A singleton set with non-zero vector is Linearly Independent   Proof :           Suppose V ( F) is a vector space and S = {𝜶} is a subset of V where 𝜶 ≠ 0 .         Now we prove S is Linearly Independent.          For a 𝞊 F such that a𝜶 = 0                                      ⇒ a=0 or 𝜶 = 0  .          Since 𝜶 ≠ 0 , we have a = 0.            ∴ S is Linearly Independent.                                               ***Hence the proof ***      Explanation :           Linearly independent set means if the linear combination of vectors is ...

Cayley- Hamilton Theorem : B.Sc. Mathematics : Linear Algebra #linearalgebra #cayleyhamiltontheorem

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  For a video explanation, click here 👉 https://youtu.be/NIQCW-Jg9yo                               Cayley-Hamilton Theorem :  Statement :     Every square matrix satisfies its characteristic equation Proof :        * Basis Extension Theorem   * V/W forms a vector space  *  Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2  } forms a basis of V3 ( F )