The Mangoldt Function ⴷ ( n ) : Number Theory #The #Mangoldt #Function #ⴷ ( n ) : #Number #Theory
Mangoldt Function : Definition
For every n ≥ 1 we define
ⴷ ( n ) = { log p if n = pm for some prime p and some m ≥ 1
=
0 Otherwise
Since 1, 6, 10 can not be expressed as prime power , ⴷ( 0) = ⴷ(6) = ⴷ(10 ) = 0.
For n = 2, we have 2 = 21 = Pm , here
m = 1
∴ ⴷ ( 2 ) = log 2.
For n = 3 , we have 3 = 31 = pm , here
m = 1
∴ ⴷ ( 3 ) = log 3
For n = 4, we have 4 = 22 = pm , here
m = 2
∴ ⴷ ( 4 ) =
log 2
For n = 5 , we have 5 = 51 = pm , here
m = 1
∴ ⴷ ( 5 ) = log 5
For n = 7 , we have 7
= 71 = pm , here m = 1
∴ ⴷ( 7 ) = log
7
For n = 8 , we have 8
= 23 = pm , here m = 3
∴ ⴷ ( 8 ) = log 2
For n = 9, we have 9
= 32 = pm , here m = 2
∴ ⴷ ( 9 ) = log 3 .
Here is a short table of values of ⴷ ( n ) :
n :
1 2 3 4 5 6 7 8 9 10
ⴷ(n) : 0 log2 log3 log2 log5 0 log7 log2 log3 0
Note :
This Mangoldt’s function ⴷ
plays a central role in the distribution of primes.
Result :
If n ≥ 1,
we have log n = Σ ⴷ (d) for
d/n
Proof :
Suppose
n is a positive integer .
For n = 1 , log 1 = 0 = ⴷ (1)
i.e. the result is true for n = 1.
Assume
n > 1.
Write n = 𝚷 pk ak, 1 ≤ k ≤ p.
Log n = Σ ak log pk . -----à ①
Now
consider Σ ⴷ (d) for
d/n.
In the above sum , the only non-zero terms come from those divisors d of the form pkm for
m = 1 , 2 , 3 ,… , ak
and k = 1 , 2 , 3 , … , r.
ence Σ ⴷ (d) = Σ Σ ⴷ (pkm)
= Σ Σ log pk
= Σ ak log pk
Σ ⴷ (d) = log n. | since from ① |
*** Hence The Proof ***
* Fundamental Theorem of Arithmetic
* Historical Introduction to Number Theory
* The Mobius Function 𝝻 ( n ) .
#The #Mangoldt #Function #ⴷ ( n ) : #Number #Theory

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