Basis & Dimension : Linear Algebra : Degree #Basis #& #Dimension #: #Linear #Algebra #: #Degree
Basis :
A non-empty set S in a vector space V ( F ) is said to be a basis of V if
i ) S is linearly independent and
ii ) S spans V i.e. L ( S ) = V .
Note :
* In the above definition of a Basis, the second condition L ( S ) = V means every vector in V is a
linear combination of vectors of S.
* For the two dimensional Euclidean Space R2, for ( a , b ) in R2,we have
( a , b ) = a ( 1 , 0 ) + b ( 0 , 1 )
i.e. every element in R2, is a linear combination of S = { ( 1 , 0 ) , ( 0 , 1 ) }
Hence S = { ( 1 , 0 ) , ( 0 , 1 ) } spans R2,
Since S is clearly linearly independent S is a abasis for R2, and this basis is called STANDARD BASIS.
* For the two dimensional Euclidean Space R3, for ( a , b , C ) in R3,we have
( a , b , c ) = a ( 1 , 0 , 0 ) + b ( 0 , 1 , 0 ) + c ( 0 , 0 , 1 )
i.e. every element in R3, is a linear
combination of S = { ( 1 , 0 , 0 ) , ( 0 , 1 , 0 ) , ( 0 , 0 , 1 ) }
Hence S = {
( 1 , 0 , 0 ) , ( 0 , 1 , 0 ) , ( 0 , 0
, 1 ) } spans R3 .
Clearly S is linearly
independent.
Hence S is a basis for R3 and
this basis is called the STANDARD BASIS
for R3 .
* Similarly For Rn , n-dimension
Euclidean space , S = { ( 1 , 0 ,0 , … ,
0 ) , ( 0 , 1 , 0 , … , 0 ) , … , ( 0 , 0 , 0 , … , 1 ) } is the STANDARD BASIS
for Rn .
DIMENSION :
Definition :
The number of elements of a basis of a vector space is called the Dimension of the vector space.
* For R2 , since S = { ( 1 , 0 ) , ( 0 , 1 ) } is the basis for R2 and S contains 2 elements, dimension of R2 is 2 .
* For R3 since S = { ( 1 , 0 , 0 ) , ( 0 , 1 , 0 ) , ( 0 , 0 , 1 ) } is the basis for R3 and S contains 3 elements, dimension of R3 is 3 .
*Similarly for Rn , S = { ( 1 , 0 ,0 , … , 0 ) , ( 0 , 1 , 0 , … , 0 ) , … , ( 0 , 0 , 0 , … , 1 ) } is the basis for Rn , S contains n elements , the dimension of Rn is n .
* Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2 } forms a basis of V3 ( F ).
* Theorem on Linear Dependence
* Historical Introduction to Linear Algebra
* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W
to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒ 𝜶 - 𝞫 𝞊 W
* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W
to be a subspace of V is 𝜶 𝞊 W, 𝞫 𝞊 W ⇒ a𝜶 +b𝞫 𝞊 W
* Problem 1 on subspace of a vector space
* Problem 2 on subspace of a vector space
* Intersection of subspaces is again a subspace
* union of subspaces of a vector space
* Problems on linear combination
* Pairwise sums of Linearly Independent Vectors
#Basis #& #Dimension #: #Linear #Algebra #: #Degree
#vector #algebra #vector algebra #iit #jee #mains #dimension #basis #subspacec #linearalgebra

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