Basis & Dimension : Linear Algebra : Degree #Basis #& #Dimension #: #Linear #Algebra #: #Degree

For a video explanation, click here 👉https://youtu.be/3ByCs2ILhgo

 Basis  :   

 A non-empty set S in a vector space V ( F ) is said to be a basis of  V if

    i ) S is linearly independent   and 

  ii  ) S spans V i.e. L ( S ) = V .                                 

 Note  :     

    * In the above definition  of a Basis, the second condition L ( S ) = V means every vector in V is a 

        linear combination of vectors of S. 

    * For the two dimensional Euclidean Space R2, for ( a , b ) in R2,we have

                  ( a , b ) = a ( 1 , 0 ) + b ( 0 , 1 ) 

             i.e. every element in R2, is a linear combination of S = { ( 1 , 0 ) , ( 0 , 1 ) } 

              Hence S = { ( 1 , 0 ) , ( 0 , 1 ) } spans R2,

            Since S is clearly linearly independent S is a abasis for R2, and this basis is called STANDARD              BASIS. 

      * For the two dimensional Euclidean Space R3, for ( a , b , C  ) in R3,we have

                  ( a , b , c ) = a ( 1 , 0 , 0  ) + b ( 0 , 1 , 0  ) + c ( 0 , 0 , 1 )

             i.e. every element in R3, is a linear combination of S = { ( 1 , 0 , 0 ) , ( 0 , 1 , 0  ) , ( 0 , 0 , 1 ) } 

              Hence  S = { ( 1 , 0 , 0 ) , ( 0 , 1 , 0  ) , ( 0 , 0 , 1 ) } spans R3 .

         Clearly S is linearly independent.

         Hence S is a basis for R3 and this basis is called the STANDARD BASIS  for R3 .

       * Similarly For Rn , n-dimension Euclidean space , S = {  ( 1 , 0 ,0 , … , 0 ) , ( 0 , 1 , 0 , … , 0 ) , …             , ( 0 , 0 , 0 , … , 1 ) } is the STANDARD BASIS for Rn .

DIMENSION :  

     Definition : 

                 The number of elements of a basis of a vector space is called the Dimension of the vector                          space.

     * For R2 , since S = { ( 1 , 0 ) , ( 0 , 1 ) }  is the basis for R2 and S contains 2 elements, dimension of          R2 is 2 .

    * For R3 since S = { ( 1 , 0 , 0 ) , ( 0 , 1 , 0  ) , ( 0 , 0 , 1 ) } is the basis for R3 and S contains 3                     elements, dimension of R3 is 3 .

     *Similarly for Rn , S = {  ( 1 , 0 ,0 , … , 0 ) , ( 0 , 1 , 0 , … , 0 ) , … , ( 0 , 0 , 0 , … , 1 ) } is the basis         for Rn  , S contains n elements , the dimension of Rn is n .  

  Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2 } forms a basis of V3 ( F ).

 * Theorem on Linear Dependence 

* linear sum of subspaces

* What is a vector space

* linear span of a set 

  * L ( S ) = L ( S' )

 * Theorem on vector space  

 * Historical Introduction to Linear Algebra

 * Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W 

            to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒  𝜶 - 𝞫 𝞊 W

                                                     (ii) a 𝞊 F , 𝜶 𝞊 W ⇒ a𝜶 𝞊 W.

* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W 

    to be a subspace of V is  𝜶 𝞊 W, 𝞫 𝞊 W ⇒  a𝜶 +b𝞫 𝞊 W

 * Problem 1 on subspace of a vector space 

* Problem 2 on subspace of a vector space

 * Intersection of subspaces is again a subspace

  * union of subspaces of a vector space

  * Problems on linear combination

 * Pairwise sums of Linearly Independent Vectors 










































































#Basis #& #Dimension #: #Linear #Algebra   #: #Degree 

#vector #algebra #vector algebra   #iit #jee #mains #dimension #basis #subspacec #linearalgebra                            


    

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