Basis Extension Theorem : Linear Algebra : Degree #Basis #Extension #Theorem #: #Linear #Algebra #: #Degree

For a video explanation ,click the link 👉 https://youtu.be/nFliuHhXhRc?si=_Ktb9UG9aDTYf6Lw


 

Basis Extension Theorem :

Statement : 

            Let V ( F ) be a finite dimensional vector space and  S = { 𝜶1, 𝜶2, … , 𝜶n } a linearly independent subset of V.  Then S is itself a basis or it can be extended to form a basis of V. 

Proof  :

 



* Find the coordinates of 𝜶 = (4 ,5 ,6) w.r.t.  x=(1,1,1),y = (-1,1,1),z = (1,0,-1) 

*  If 𝜶 = ( 1 , -1 , 0 ) , 𝜷 = ( 2 , 1 , 3 ) find a basis for R3 containing 𝜶 and 𝜷 

*  Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2  } forms a basis of V3 ( F )

 * Theorem on Linear Dependence 

* linear sum of subspaces

* What is a vector space

* linear span of a set 

  * L ( S ) = L ( S' )

 * Theorem on vector space  

 * Historical Introduction to Linear Algebra

 * Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W 

            to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒  𝜶 - 𝞫 𝞊 W

                                                     (ii) a 𝞊 F , 𝜶 𝞊 W ⇒ a𝜶 𝞊 W.

* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W 

    to be a subspace of V is  𝜶 𝞊 W, 𝞫 𝞊 W ⇒  a𝜶 +b𝞫 𝞊 W

 * Problem 1 on subspace of a vector space 

* Problem 2 on subspace of a vector space

 * Intersection of subspaces is again a subspace

  * union of subspaces of a vector space

  * Problems on linear combination

 * Pairwise sums of Linearly Independent Vectors 





















































































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#Eigenvectors
#MatrixAlgebra
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#basisextension theorem, #linear algebra #iitjee #mains #mathematics

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