Find the coordinates of 𝜶 = (4 ,5 ,6) w.r.t. x=(1,1,1),y = (-1,1,1),z = (1,0,-1) :linear algebra : Degree
Problem
Find the coordinates of 𝜶 = (4 ,5 ,6) w.r.t. x=(1,1,1),y = (-1,1,1),z = (1,0,-1).
Solution :
* If 𝜶 = ( 1 , -1 , 0 ) , 𝜷 = ( 2 , 1 , 3 ) find a basis for R3 containing 𝜶 and 𝜷
* Show that the set { ( 1 , 2 , 1 ) , ( 2 , 1 , 0 ) , ( 1 , -1 , 2 } forms a basis of V3 ( F )
* Theorem on Linear Dependence
* Historical Introduction to Linear Algebra
* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W
to be a subspace of V are (i) 𝜶 𝞊 W, 𝞫 𝞊 W ⇒ 𝜶 - 𝞫 𝞊 W
* Let V(F) be a vector space and let W ⊆ V. The necessary and sufficient conditions for W
to be a subspace of V is 𝜶 𝞊 W, 𝞫 𝞊 W ⇒ a𝜶 +b𝞫 𝞊 W
* Problem 1 on subspace of a vector space
* Problem 2 on subspace of a vector space
* Intersection of subspaces is again a subspace
* union of subspaces of a vector space
* Problems on linear combination
* Pairwise sums of Linearly Independent Vectors
#Find #the #coordinates #of #𝜶 = #(4 ,5 ,6) #w.r.t. #x= #(1,1,1), #y = #(-1,1,1) #, #z #= #(1,0,-1)

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