Wilson's Theorem : Number Theory #Wilson's #Theorem #: #Number #Theory
Wilson’s Theorem :
Statement :
If p is a prime then
(p-1)! + 1 = 0 ( mod p )
Proof :
Suppose p is
a prime number..
For p=2, we have
(p-1)! + 1 = 2 and 2 ≡ 0 ( mod 2 )
i.e. the statement
is true for p=2.
Let p > 2 and a 𝟄 Z such that 1 ≤ a ≤
p-1.
Since p is
prime , we have (a,p) = 1 and hence the linear congruence ax ≡ 1 ( mod p) has
unique solution,
say x0.
Let a’ 𝟄
x0— and 1 ≤ a’ ≤ p-1 where x0— is
the congruence class of x0.
Clearly aa’ ≡ 1 ( mod p )
a’ = a
ð
a2 ≡ 1 (
mod p )
ð
p / a2-1
ð
p/(a-1) or p/ (a+1)
for p/(a-1) and a
> 0 => a+1 = p
ð
a = p-1
∴ a’ = a
ð
either a = 1 or a= p-1
similarly if a’ ≠
a then a 𝟄 { 2,3,…,p-2}.
∴ the distinct a , a’
belong to the set { 2,3,…,p-2} containing (p-3) elements.
These (p-3)
elements form (p-3)/2 pairs, such that the product of each pair ≡ 1 ( mod p ).
Multiply these
(p-3)/2 congruences, we get
2.3….(p-2) ≡ 1 (
mod p )
=> 1.2.3….(p-2)
(p-1) ≡ 1 (p-1) ( mod p )
=> (p-1)! ≡ (p-1)
( mod p )
=> (p-1)! + 1 ≡
p ( mod p )
=> (p-1)! + 1 ≡
0 ( mod p ).
***
Hence The Proof ***
Note :
The converse of the above theorem is also
true i.e. (p-1)! + 1 ≡ 0 ( mod p ) implies p is prime.
* Fundamental Theorem of Arithmetic
* Historical Introduction to Number Theory
* The Mobius Function 𝝻 ( n ) .
#Wilson's #Theorem #: #Number #Theory

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